Let Ft = force of tension Fg = weight Fnet = net centripetal force
The key is to break the tension force into vertical and horizontal components. The vertical component will be equal to the weight. The horizontal component will be equal to the net centripetal force. If you write an...
Yes, that is exactly what you would do! And if there was an acceleration up the slope(and parallel to it) as well as friction opposing the motion,then the applied force would equal the sum of the friction force, the component of gravity parallel to the ramp and the net force. The net force would...