Recent content by celestra

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    Solve Markov Chain Problem: Find Initial Probability Vector p(1)

    I did a mistake. You're right EnumaElish. :wink: Any Q has it's own eigenvectors at least one. So your stationarity assumption will be okay. And it seems the best idea for my problem currently.
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    Solve Markov Chain Problem: Find Initial Probability Vector p(1)

    I don't like the stationarity assumption because I want to deal with a sequence even like this: 010100100100000000000000000000000110100101.
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    Solve Markov Chain Problem: Find Initial Probability Vector p(1)

    What about MAP(Maximum A Posteriori) esimation, \hat{x}=argmaxp(x|y), since we're interested in the random variable x, p(1) in this case, given data as the realization y, in this case the sequence? I feel like this will work. The a posteriori pdf p(x|y) can be calculated using Bayes's theorem...
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    Solve Markov Chain Problem: Find Initial Probability Vector p(1)

    For example, you are given this sequence: 010100101101001011010010111010. Then, you can get Q as [3/14, 11/15; 11/14, 4/15]. And, I have no idea how I can get p(1) from this. Additionally, is it possible anyway?
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    Solve Markov Chain Problem: Find Initial Probability Vector p(1)

    It's a good idea. You can use any sequence if it is composed of zeros and ones.
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    Solve Markov Chain Problem: Find Initial Probability Vector p(1)

    Oh, I forgot that. The realization is not deterministic but stochastic through a kind of random number generation according to the probability vector. If p1=.4 and p2=.6, then the probability that a zero will come out is 40 percent and the probability that a one will come out is 60 percent.
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    Perpetual Motion: U-Tube Water Capacitor Experiment

    I was somewhat serious when I was posting it if the water will really circulate. However, now I get to know it will not, thanks to the cesiumfrog's explanation. :smile:
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    Solve Markov Chain Problem: Find Initial Probability Vector p(1)

    [SOLVED] Markov chain problem Hi, all! This is not a homework thing or something like that. I'm just curious. Suppose a Markov chain p(n+1)=Q*p(n), where Q=[q11, q12; q21, q22] is the transition probability matrix and p(n)=[p1(n);p2(n)] is the probability vector. Given Q and p(1), we can...
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    Electromagnetic Momentum & Force: QM & Wave Analysis

    Electromagnetic momentum according to QM: p=\frac{h}{\lambda}=\frac{h}{c}f And force is time derivative of momentum: F=\dot{p} Then, is F=\frac{h}{c}\dot{f}(i.e., electomagnetic wave of which frequency is being increased) can be viewd as a force? What kind of force is this? Electromagnetic...
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    Perpetual Motion: U-Tube Water Capacitor Experiment

    But, the electricity doesn't have any load. It seems that it supplies no work, i.e., no energy at all.
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    Perpetual Motion: U-Tube Water Capacitor Experiment

    There is a U-tube which contains pure water of about half of its volume. And let's put a capacitor around one surface of the water in the tube. If we apply a high dc voltage to the capacitor, the surface of the water in one side of the tube rises slightly because the permittivity of water is...
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    Violation of action-reaction law?

    Please, check me if I'm right. Let the directions of the two forces on q1 and q2 be in north-east. Then the total momentum of the two charges are in the same direction. And the total momentum of the two fields are in the opposite direction, south-west(I'm not sure). So, the total momentum of the...
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    Linear momentum and angular momentum

    I think I had another mistake in the above mention. Let me ask the final question that IF I MAY SAY that some portion of the angular momentum(L) was CHANGED to linear momentum(p) according to the relation L=rxp(where r is the radius of the ball), AS I CAN SAY that some portion of the angular...
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    Violation of action-reaction law?

    Two equally positively charged points are moving on a plane at a constant speed. One of them (q1) is heading towards south, the other one (q2) towards west, and they're approaching to each other. Then, magnetic fields are induced from these moving charges. And Lorentz forces on q1 and q2...
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    Linear momentum and angular momentum

    Thank you for your correction. Lt2 = Lb2 - Lb1 < 0 Pt2 = Pb1 + Pb2 > 0 Now I accept from your explanation that above two relations are totally independent from each other. So, one of them cannot influence the other. And I understand that I cannot predict the movement of the ball unless...
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