Recent content by cgr4

so a = 27 so, y = 27(-3) + b -27 = -81 + b therefore b = 64?

The line y = ax + b is tangent to y=x3 at the point P = (-3,-27). Find a and b. I'm pretty lost on this one. Here's my initial thoughts. Find (a) first. (a) is equal to the slope which is the derivative of x3 So (a) would be equal to 3(-3)2 ? Not quite sure where to start on this one.

So here's the question. In industry, the relationship between wages and the quit ratio of employees is defined to be the percentage of employees that quit within 1 year of employment. The quit ratio of a large restaurant chain that pays its employees the minimum wage \$6.55 per hour was .2 or...

resulting in 125x-1y 125yx 125y over x

Still a little confused about the 2nd problem. So 125x(3/2-2)y(3/2-2) correct?

For the second question. It would look something like this? 125x3/2y3/2x2y then I would subtract x2 and y which would equal 125x1/2y ?

(9x)^-1/2 So, I'm not entirely sure how to go about this question. It's got a negative exponent, so I assume its 1 / something. My guess for the answer would be: 1 / 3x [(25xy)^3/2] / x2y For this question, would I compute 253/2 and then x3/2 y3/2 and then divide by x2y