@TheDS1337
Is actually one function Z(x,y), but "y" itself is a function of "x" (unknown at this time)
What I am trying to find as the "solution" to this PDE is Z(x,y), i.e. something like "...Z(x,y) = A*cos(y-wx) + exp(-y*x)..." or something like that.
Note that the first 2 parts of the PDE...
as you can see, z(x,y) is a function of x, y; and y is a function of x, therefore y'(x) is the total derivative of "y" respect to "x", and y"(x) is the 2nd derivative. y'(x)^2 is just the square of the derivative of y respect to x
I don't have boundary or initial conditions, so you can make up...
Hello, I was looking for a PDE solution that has eluded me for some time, and came across this amazing forum. I am hopeful that I will find great topics to discuss here and thank you all in advance