Recent content by charlie05

the full text of the task reads: : a rectangle ABCD and points E, F such that triangles BEC and CFD are equilateral and each of them has only one side in common with the rectangle ABCD. Reason that triangle AEF is also equilateral.

by attachment I mean the task text listed below under the heading, there is no other attachment, sorry for the mistake

Given a rectangle ABCD and points E, F such that the triangles BEC and CF D are equilateral and each of them has only one side in common with the rectangle ABCD. Justify that triangle AEF is also equilateral.

ad B/equilibrium iodine concentration found during titration ? reaction of titration: 2 S2O32−(aq) + I2(aq) → S4O62−(aq) + 2 I−(aq) 2 moles of thiosulfate react with 1 mol I2 consumption of thiosulphate... 14,5 ml 0,075 mol/dm3 solution...0,0010875 mol of thiosulfate equilibrium iodine...

so in the solution of I2 in KI I have to count only with the concentration of the original I2?I don't have to count on the amount of KI? concentration of the iodine solution...2,5424 g I2 in 100g of solution...25,424 g/dm3 I2...?

1/ iodine stock solution: mixed 2,5424 g I2 and 24,1525 g KI and made up to 100 ml with water 2/ 150 mg active carbon is mixed with 12,5 ml jodine solution from point 1 / 3/ At equilibrium were performed filtration and titration with 10 ml of the filtrate with a volumetric solution Na2S2O3...

:-) i understand...

I still have a question - what is the driving force of decomposition of intermediates to the product ... is it the formation of NaCl?

Yes, thank you very much... Intermediate product...?

product is methylpropionate and NaCl?

Yes thank you...an intermediate product is formed - anion CH3O is bound to the positive carbon, to the negative carbonyl oxygen is bounded Na +? or does sodium bind to chlorine?

sorry, I do not understand...

the nucleophile binds to an electrophilic carbon...nucleophile is CH3O ?

nucleophilic addition...C is δ+ and O is δ-