Recent content by Chaubin

I know the derivative of sqrt(4-x) is -1/(2*sqrt(4-x)). After this I get a bit foggy on the procedure. I think I have to use the product rule f(x)*g(x)= f(x)*g'(x) + f'(x)*g(x) In this case f(x) = x and g(x)= sqrt(4-x). So it should be: x*(-1/(2*sqrt(4-x)) + 1 * sqrt(4-x) correct?

Ok, i think I finished it. I ended up with (x/((2 * sqrt(4-x))) + sqrt(4-x)

So, I take the quantity (4-x)^1/2 and turn it into (1/2)*(4-x)^-1/2? Is that it?

Homework Statement Find the derivative of g(x)=x * sqrt(4-x)Homework Equations The Attempt at a Solution I know I use the product rule, but I am not sure how to derive the sqrt(4-x) portion.