Recent content by cheab14

ohk i'll keep (1) in mind when I work it out again thank u! and number (2)-couldn't believe it was that simple..thank u thank u thank u!

lol ok...i needed a way to remember those formulas...but i have two other questions: one involving proving identities...n the other involving expressions: (1)prove the identity: tan(x-y) + tan(y-z) + tan(z-x) = tan(x-y) tan(y-z)tan(z-x) for this i started using the subraction formula on the...

ok thank u much!

hello tiny-tim! for (1) i worked out the LHS like so: (cosxcosy - sinxsiny)(cosxcosy + sinxsiny) which ended up being: cos(^2)x cos(^2)y - sin(^2)x sin(^2)y. And then I'm stuck. for (2) I'm just lost:confused: -I have: sinxcosy + cosxsiny + sinycosz + cosysinz for the LHS which makes no...

The question states, "Prove the identity." (1) cos(x + y) cos(x-y) = cos(^2)x – sin(^2)y. Should i start off using the addition and subtraction formulas for the LHS, and breaking down the perfect square for the RHS? If not or if so, how would I go about solving this problem? Step by step...

question 2 write an equation for the line that contains (0, 3) and is perpendicular to the line 6x-2y=1. So for this question, I've found the slope of the line 6x-2y=1 which was 3. But would the slope for line (0, 3) be -1/3?

ok thank u!

The question reads: find the value of k to make the points (3,9) (7, k), and (-1,6) collinear. Does this involve using the distance formula? Whether or not it does, how would I go about solving this problem?

...thank u guys

ok but cristo, for (a) you're saying that my centre would just be p and q?..no actual numbers?...and for (b) my radius would be 9? -also for (b) what would be my centre after completing the square for the y component?

The question states: Find the centre and radius of each circle with equations as given (a) 3x^2 + 3y^2 = 81 (b) x^2 = 6y - y^2 I really don't know how to approach this question, i started (a) by dividing both sides by 3 but then i don't know where to go from there, and i don't even know...