Recent content by chemkid01

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    Mechanism for Phosgene Formation

    Got it, thank you!
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    Mechanism for Phosgene Formation

    The overall reaction for the formation of phosgene from Cl2 and CO is: Cl2 + CO --> Cl2CO The mechanism is: Cl2 + M <--> 2Cl' + M Cl' + CO <--> ClCO' ClCO' + Cl2 --> Cl2CO + Cl' For this mechanism, the sum of the elementary reactions is: 2Cl2 + CO --> Cl2CO + 2Cl' However, doesn't the sum...
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    Entropy change in a irreversible adiabatic process

    Hmm, ok, I don't think I quite understand reversibility. Could you explain what it is about the path being reversible that makes it so you won't be able to hold the temperature constant? Also, on a side note, since a reversible, isothermal expansion does bring you from the same initial state to...
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    Entropy change in a irreversible adiabatic process

    Ok, thanks for the help! One more thing, I'm not exactly sure what makes a process reversible/irreversible. For example, the question says that it is an irreversible, adiabatic expansion from 1.0 L to 10.0 L. Why can't my alternate reversible path simply be a reversible, adiabatic expansion from...
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    Entropy change in a irreversible adiabatic process

    Ok, so for this case, since the process is adiabatic and q = 0 and no work is done, then delta U = q + w = 0. And since it's an ideal gas, U only depends on T so T is constant as well. So could my dreamed up reversible process be a reversible isothermal expansion from 1.0 L to 10.0 L at 298 k?
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    Entropy change in a irreversible adiabatic process

    One mole of an ideal monatomic gas initially at 298 k expands from 1.0 L to 10.0 L. Assume the expansion is irreversible, adiabatic, and no work is done. Calculate delta S of the gas and delta S of the surroundings. I know that delta dS = dq/T but q = 0 in adiabatic processes right? So does dS...
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