Recent content by chenel

Nope. Be careful: you're mixing \hat{k}'s and \vec{k}'s with abandon! Remember that \hat{k} = \frac{\vec{k}}{k} ... that should straighten you out.

Whoops, what I meant was \hat{k} \times \hat{k} \times \vec{f}(\vec{k}) = \hat{k}(\hat{k} \cdot \vec{f}) - \vec{f} \left|\hat{k}\right|^2 = \vec{f_{\parallel}} - \vec{f} Note that it's \vec{f} minus its LONGITUDINAL component that makes the the transverse component. @gabbagabbahey: oh...

There's no problem. \hat{k} \times \hat{k} \times \vec{f}(\vec{k}) = \hat{k}(\hat{k} \cdot \vec{f}) - \vec{f} \left|\hat{k}\right|^2 = \vec{f_{\perp}} - \vec{f} which is the negative of the transverse component. You're only missing a minus sign somewhere.