Recent content by chikis

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    His average speed for the first 4km is what?

    Solving that way we make us to have two unknowns and that will make the problem too dificult to solve.
  2. C

    His average speed for the first 4km is what?

    (1-t) is nothing more than subtracting the time for the first 4km from the total time, which gives the time for the last 5km.
  3. C

    Instantaneous velocity and a catapult

    You did not define some variables in the equation: (kx^2)/x = kx/2 How come that equation? I believe k is constant. But what is x?
  4. C

    His average speed for the first 4km is what?

    I know that t represent time. Am now asking 1-t is what?
  5. C

    His average speed for the first 4km is what?

    Please expanciate a little bit. What is the thinking behind the expression (1 - t) ?
  6. C

    Instantaneous velocity and a catapult

    So how do we go about it? By the way, what is the difference between average force and peak force?
  7. C

    His average speed for the first 4km is what?

    4/x +(5/x 2) = 1 9x+8 = x2+2x x2 - 7x - 8 = 0 (x 1)(x-8) = 0 x = 8 or x = -1 The correct answer is 8 km/h. My observation here is that we can only make equation for the total time and use it to find the speed. Why is that if we make equation for the total distance (as I did...
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    Instantaneous velocity and a catapult

    Yes it did. It gave 44.27 ms-1 as the answer.
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    LaTeX Showing Symbols: Square Root, Super/Sub Scripts, LaTeX

    How do I indicate or show square root sign, super script and sub script? How do I use latex in the forum?
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    Instantaneous velocity and a catapult

    Homework Statement A stone of mass 5 g is projected with a rubber catapult. If the catapult is streched through a distance of 7 cm by an average force of 70 N, calculate the instantaneous velocity of the stone when released. Homework Equations work done in elastic material w = 1/2 fe =...
  11. C

    His average speed for the first 4km is what?

    A man runs a distance of 9km at a constant speed for the first 4km and then 2km/h faster for the rest of the distance. The whole run takes him one hour. His average speed for the first 4km is what? Total distance = 9km Total time = 1 h For the 1st for 4km, he moved at a constant...
  12. C

    Understanding Velocity Ratio and its Impact on Lever Orders

    But I believe that would have the same explanation with the first statement I gave in disguise.
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    Understanding Velocity Ratio and its Impact on Lever Orders

    So do we say this is the most acceptable explanation for now?
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    Understanding Velocity Ratio and its Impact on Lever Orders

    Exuse me! Let's get something correct here. Does"1 times greater than", means "equal to" or "more than"? When we say "1 times the load", that could mean equal to the load rather. How do you look at that?
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