Sorry - I s'pose I should have given that.
I divided .361/15 and took the arcsine of that. I'm getting 1.37 degrees. Looks like my previous answer (that was in thousandths of degrees) was because my calculator was still in rads. Still though, I'm really off by at least half.
I already have the wavelength but that's not what the problem is asking for. Its asking for the angular width of the wavelength. I'm getting an angle with four decimal places which isn't anywhere near what the book gets or even what seems right.
Homework Statement
You need to use your cell phone which broadcasts an 830 MHz signal but you're in an alley between two massive radio wave absorbing building that have only a 15m space between them. What is the angular width in degrees of the electromagnetic wave after it emerges from between...
Okay, so you're saying that because I know that all the energy ends up as m2gy, then all the kinetic energy of ball two immediately after impact should be equal to that and therefore:
m[SIZE="1"]2gy = 1/2m[SIZE="1"]2(v[SIZE="1"]f2^2)
Is that right?
EDIT: Thanks for the response, btw.
EDIT 2...
Homework Statement
A 20g ball is fired horizontally with initial speed v[SIZE="1"]i toward a 100g ball that is hanging motionless from a 1.0m long string. The balls undergo a head-on, perfectly elastic collision after which the 100g ball swings out to a maximum angle of 50degrees. What was...