The question is:
Show that:
\int_0^1\int_x^1e^\frac{x}{y}dydx=\frac{1}{2}(e-1)
I've tried reversing the order of integration then solving from there:
\int_0^1\int_y^1 e^{\frac{x}{y}}dxdy
=\int_0^1[ye^\frac{x}{y}]_y^1dy
=\int_0^1ye^\frac{1}{y}-ye^1dy
But I can't integrate...