Recent content by cholyoake

Oh of course, thank you very much for your help.

The question is: Show that: \int_0^1\int_x^1e^\frac{x}{y}dydx=\frac{1}{2}(e-1) I've tried reversing the order of integration then solving from there: \int_0^1\int_y^1 e^{\frac{x}{y}}dxdy =\int_0^1[ye^\frac{x}{y}]_y^1dy =\int_0^1ye^\frac{1}{y}-ye^1dy But I can't integrate...