Recent content by chrispsu

oh ok...the heat of fusion should be 333x10^3...solving it out then i would get 2.11 which is the correct answer. I need to be less careless with my units! lol thanks alot! :D

im reviewing for my final in a few days an although this is a basic question i can't work out the correct answer for some reason. and i know i started the other thread below this one but i figured this was a different topic so the heading should be different lol Homework Statement A heat...

oh wow sorry i had no idea this went to 2 pages lol just thought there was no response :o anyhow quartering the initial pressure worked! thanks! and yea i copied and pasted it straight from the hwk since it is online. Many people have complained about this question to the professor so...

its not right lol :confused:

Doing PV=nRT i get: P(.0048-->volume quadrupled)= (1)(8.3145)(350) i get P= 606kPa?

if you or anyone else doesn't mind helping me with one more. I've already gotten it wrong on my homework as your only allowed to submit three tries but I still would like to know how to do it correctly. The problem is: One mole of a monatomic ideal gas has an initial pressure of 220 kPa, an...

oh ok awesome...i don't know why i used that other value of r, but obviously the other person who posted used it too lol thanks again! :D

oh wow that worked! thanks alot! :D ive never seen that formula before lol

ok i did: PV=nRT (1x10^5)(.0092)=n(.08206)(296) for n i am getting 37.8875 after multiplying it by 6.022x10^23 i get 2.28x10^25 which is incorrect. :(

please anyone who has any idea what I am doing wrong i would really appreciate it if you could point it out! i keep getting the same number and its an online hwk which is telling me the answer is wrong so I am stuck

Ideal Gas Law Problem :) Homework Statement A balloon is filled with helium at a pressure of 1.0 x 10^5 Pa. The balloon is at a temperature of 23°C and has a radius of 0.13 m. (a) How many helium atoms are contained in the balloon? (b) Suppose we increase the number of helium atoms in...

i keep getting 715-1274 i don't understand the part a few posts up where i use the density of air. why would i use that and where?

volume is 4/3 pi (4.6m)^3 = 407.72m^3? so how do i find the weight of the balloon then? we seriously never even came close to doing anything like this question in class, i don't understand why they would assign it:(

oh wait just realized i forgot to incorporate g so i would do 715-1274?? that doesn't sound right?

ok i solved for the volume of the balloon and got 407.72 next i multiplied the volume by the density given (.179) and got 72.98 B-weight= 72.98- 1.274 = 71.7