thanks.
is that mean 2 orbitals with one occupied by 2 electrons and other with electron occupied singly,
and 2 orbitals both single occupied.
The repulsion between the latter one is greater than the former one?
I want to ask which type of the following would have a greater repulsion
electrons with parallel spin, electrons with opposite spin.
or it's just the same?
well i find that the original configuration i proposed should be correct since the atom tends to retain the extra stability of fully filled 3d subshell...
so now the new configuration is
Cu+:3d^8 4s^2
Cu2+:3d^7 4s^2
cu2+ has 3 unpaired 3d electrons whereas Cu+ has 2 unpaired electrons, in theory the unpaired electrons in Cu2+ will repelled from the inner electrons and thus more unstable?
Homework Statement
Explain why copper(II) is the more common oxidation state than copper (I) by giving the electronic configurations of the ions involved.
The Attempt at a Solution
i've considered about the configurations of Cu+ and Cu2+ but the result seems to contradict the fact...