Recent content by chrizzilla

wow... that's correct. why did I not see that? I feel like an idiot now... Thank you so much good sir.

Oops, you're right, that's my bad. You will have to forgive me, I misunderstood what you meant by "given." I assumed that you were seeing that these were given as numbers somewhere. using V0=30I3 and substituting for I3 I get 30*((120*Is -Vs)/(150))=a*i_{s}+b*V_{s} or...

hmm, well, that is not what I have gotten. solving for I2 using the second equation, I get i_{2} = \frac{96*i_{s}+V_{s}}{128} and then using that in the third equation, I get i_{3} = \frac{960*i_{s}-V_{s}}{1920}, which is nowhere near what you got. Also, everyone keeps saying Is and Vs are...

Hmm, I am confused. I know that V0=30*I3 and Is=I1, but I don't know how to get V, so I can't actually get Vs.

Homework Statement The circuit shown has two inputs, V_{s} and i_{s} and one output V_{o}. The output is related to the input by the equation V_{o}=ai_{s}+bV_{s} where a and b are constants to be determined. determine the values a and b by (a) writing and solving mesh equations and (b) writing...

Nevermind, I figured it out. Since we are looking at the tension between the second and third cars, we only have to look at the force of 13 cars. You simply have to multiply the weight of one car by 13 and use the equation F=ma to calculate: F = (13)(37,000kg)(.72m/s^2) F= 346,320 N

Homework Statement A locomotive is pulling 15 freight cars, each of which is loaded with roughly the same weight. The mass of each can be taken to be 37,000 kg. If the train is accelerating at 0.72 m/s^2 on a level track, what is the tension in the coupling between the second and third cars...