Recent content by Cicima

can u show me the steps because i still can't get that answer...i get like 7.139x10^13, then i multiply it by 70 and 9.8 and divide it by (6.4x10^6)^2 and get 1195. Howd u get 1.07x10^27? What do you do after you get it? if u plug it into the 2nd equation you get a crazy number.

can u show me the steps because i still can't get that answer, after that i know how to do it...thanks.

1.07 x 10^27 kg now needs to be multiplied by m12 which is 70kg. so can i just multiply 1.07x10^27 by 70, then divide it by r^2 and that's it? Quick question, if I am doing R^2, would that mean if r is 6.4x10^6 that r^2 is 6.4x10^12?

Then... Gm1=39.478 r^3/3456000^2 Gm1=39.478 r^3/1.194x10^13 then you divide each side by G...so what am i doing wrong? Maybe I am taking r^3 wrong? How do you do that just to make sure I am doing it right.

Oops forgot G. Gm1=4pi^2 r^3/t^2 That would be simplified then...so why does my answer look so wrong when i plug in 345600 for t, and 6x10^8?

m1/r^2=4pi^2 r/t^2 thats basically as far as i can solve it... plug in 345600 for t, and 6x10^8 for r, then its just basic calculator plug ins from there getting m1/r^2=.0019...so what am i doing wrong?

So am i wrong? And if so, where am i plugging them in wrong?

Yes that's what i meant. The other r (the one in the 2nd equation) is the radius. So i know how to set it up, the problem is I am not good at plugging it in. What am i doing wrong? m1/3.6x10^17=39.47 r/t^2 m1/3.6x10^17=39.47 (6x10^8)/1.194x10^13 when i solve for m1 i get 6.84x10^14...that...

Im not sure if this is done right... Im guessing use Net force = ma The net force is the Gravitational force, Gm1m2 / r^2 is = m2 4 (pie)^2 r/ T^2 for the 4 (pie)^2 r/ T^2 r is the distance form the planet's center, to the moon, for T, find how many second 40 days is. and the other r...

Can someone please help me do this problem? So far i got... the fireman is accelerating such that ma=mg-800N i think i have to find a, but i don't know how to, can you guys help me find it? after i find a, i can find v by doing d=v^2(2a) where D is 10m, but i don't know how to find a so...

I got this problem as part of a long homework packet, was able to figure out all the problems but the last 3, so here is one of them, but i don't have a book. I really have no idea on how to approach this problem, so i was hoping someone could lead me through it and help me figure it out... I...

Ok so using that formula, d=v_it+\frac{1}{2}at^2 D=.5(1.03)(10)(10) D=51.5 So would that mean the location of the motorboat is 51.5 (what unit?) away from where it was orginally after 10 seconds? And with the angle, i got -.004 with the tangent equation of tan.25*-1...how does that...

Ok so using f=ma, the acceleration should be...1.03. Which of those equations should i use? I don't have a textbook, so I am not certain. Also, how does the angle help me in this problem, it isn't part of any equation is it? Can you help me set up the final equation using 1.03, or tell me which...

You get 2061.55 adding the two vectors together using the pythagorean theorem, but what steps do i take next to solve this? I still can't figure it out.

Ok, so force = mass * acceleration. What would the force be in that equation, since there are 2 different forces, one pushing west 2000N and one pushing south 500N? Thats what i didnt understand when putting together the acceleration.