I'm creating a computer program and I need to see what's most efficient. I need another program [lol] that I can input 3d points in and have it create the function.
the points are this v e t
100 500 3...
Yea, they always execute with the length of the original number but with 8 at the end then the length of the number, with a 1 at the end terminating it.
ie. 9*9=81
99*99=9801
999*999=998001
9999*9999=99980001
99999*99999=9999800001
I know, and conform to the ideal that .9 infinitely repeating does in fact equal 1 but I have a thought that keeps bothering me.
How can.9999999999999999999999999999999999999999999999999999999(repeating forever) multiplied by 2, equal 2?