A constant net force will yield acceleration (+'ve or -'ve)
The car traveling at 60km/hr has no net force acting on the vehicle. While the car accelerating to 60km/hr has a net positive force (acceleration) until the moment the clutch is engaged.
Sorry the above thread was suppose to show spaces - allowing the visualisation of car A relative to car B
Time 0
----------(A) 0km/hr
(B) 60km/hr
Time 1
-------------------(A)30km/hr
------------(B) 60km/hr
Time 2
--------------------------(A)60km/hr
--------------------------(B)60km/hr
Time 0
(A) 60km/hr
(B) 0 km/hr
Time 1
(A) 30km/hr
(B)60km/hr
Time 2 (all power removed)
(A)60km/hr
(B)60km/hr
Does it make sense that car A would now pass B? This is how car A is going backwards relative to car...
ltw97m3
You are probably accurate in that your car appears to be accelerating from the speedometer, however there is a slight delay in the real-time display of this device.
Try the opposite to accelerating - but braking from 100km/hr down to 60km/hr. Coast when the speedometer reaches...