Thanks for the reply TSny.
I've considered something similar and figured it out I believe.
I used P1V11+f/2=P2V21+f/2, solved for P2, and substituted that into my Qin equation. And since there was still a P1 in there, I used the PV=NkBT for P1 to put it in terms of T1. Now my Qin satisfies all...
One thing I just realized is that for 2→3, I shouldn't have said ΔU = 0. Instead, I should have set up Qin as:
Qin = ΔU - W, where
ΔU = NkB(f/2)ΔT
ΔU = NkB(f/2)[(PV3-PV2)/NkB]
and W is still W=-P(V3-v2)
so, once simplified (Qin = ΔU - W), Qin=P[V3((f/2)+1)-V2((f/2)+1)].
This still doesn't...
1. Ideal gas cycle - diesel engine cycle. You begin at some volume V1. Perform an adiabatic compression to V2. Perform an expansion to V3 at constant pressure. Next, perform an adiabatic expansion to V4, Last, it moves back to V1 at a fixed volume, while decreasing temperature back to...