Recent content by cogs24

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    Finding G-Force & Pressure in Fluid Flow: Aluminium Sphere Case

    HallsofIvy was correct, the gravitational force is just its weight, its simple use desnity of aluminium along with its volume to find the mass, then use this is W=mg formula to find the the weight force In terms of the pressure question, i know the area and velocity of the fluid at 2...
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    How Does Adding an Aluminum Rod Affect Water Temperature and Steam Production?

    hi guys 200g copper calorimeter, 200g of water, both intially at 30 degrees. Aluminium rod added to the system, with mass of 250g, final temp is 100 degrees. 10g of water is converted to steam. first its asking to calulate how much energy is reuiqred to vaporize those 10g to steam then...
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    Finding G-Force & Pressure in Fluid Flow: Aluminium Sphere Case

    hi guys if you have an aluminium sphere of volume 0.006 metres cubed, how do you find the gravitational force acting on the sphere, as well as its acceleration (ignoring water resistance) Also, if your given the area and velocity of a fluid at two points of hose, how can you find the...
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    Is Trigonometric Substitution Needed for ∫ √9-2(x-1)²?

    so, sqrt 2u = sin theta
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    Is Trigonometric Substitution Needed for ∫ √9-2(x-1)²?

    the 2 outside the (x-1)^2 is confusing me Im not sure what my x and a squared is?
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    Is Trigonometric Substitution Needed for ∫ √9-2(x-1)²?

    hi guys im still stuck on this question, it has really got me stumped i know that for the form √a² - x².dx x=asinθ, dx = acosθ.dθ but i just can't seem to put it together
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    Is Trigonometric Substitution Needed for ∫ √9-2(x-1)²?

    2 is on the outside of the (x+1)
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    Is Trigonometric Substitution Needed for ∫ √9-2(x-1)²?

    hi guys im debating whether this question requires trignometric substitution or just normal substitution. ∫ √9-2(x-1)² Im leaning towards normal substitution, with u = x-1, but I am not sure Any ideas Thanx heaps
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    Integration by Parts: Solve x^2exp(-3x)dx

    i see, thanks for that link, i will probably apply this method from now on
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    Integration by Parts: Solve x^2exp(-3x)dx

    arbitary constant would be + c
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    Solving Definite Integral: x/sqrt(3x^2 + 4)

    hi guys yeh, I am still going through revision, and I am also stuck on this question. *integral sign*(upper limit 4, lower limit 2) x/sqrt(3x^2 + 4).dx When i look at this, i think of letting u = 3x^2 + 4, then bringing that sqrt to the top,solving for dx, and then find the integral, and...
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    Integration by Parts: Solve x^2exp(-3x)dx

    ok, I've got my answer, unfortunately i don't kow if its right, we don't get solutions for this exercise -1/3 *exponential* ^ -3x . x^2 - 1/9*exponential*^-3x . 2x - 2/27*exponential*^-3x
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    Integration by Parts: Solve x^2exp(-3x)dx

    no, i am not aware of the tabular method, sorry
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    Integration by Parts: Solve x^2exp(-3x)dx

    ok, once i sub u, du, v and dv into the integral by parts formula, i have to assign, u and dv again to: -1/3 exponential ^ -3x and 2x so is dv assigned to the exponential again, like in the first case?
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