The cool thing is that the sun doesn't really "burn" like fire does!
You're right that fires require oxygen as a reactant, but the sun runs on nuclear fusion. Nuclear fusion is the joining of atomic nuclei together and it's possible because of the high temperature and pressure in the sun's...
Hi ZapperZ!
Are the courses in college going to be similar to the way high school AP courses are structured?
I ask because my interest in the Physics and Chemistry AP classes is low.
Homework Statement
Problem:
Create a means for the egg to land on an uneven dirt surface from a great height without breaking.
Restrictions:
No parachutes (or wings, or any other velocity-slowing addition,) packing materials/padding, balloons, or thick liquid substances.
The project must...
Yeah, get rid of the applied force, and your mg X component will take care of that role for you.
Your equation shouldn't include F as one of its forces, so that's what's messing it up. :)
In the X direction, is Fnet the same as the F in F=ma?
If there's no forces acting against the force of the tension force (and it is the only X force,) then what is the net force in the X direction?
The forces don't necessarily have to add to zero on the same object (if they don't, then the net force will cause acceleration on your object instead...
After re-reading your OP, I'm sorry for replying with an incorrect response. I misunderstood your question (whoops!) :redface:
Use the equations for your X and Y components of your velocity and work out θ using trig.
Thanks for the reply. Yeah, I think it was a fault of mine. :)
There's going to be no way that plugging an arbitrary number in for 'a' will give consistent frictions or even FA depending on which is being solved for.
So, the only question I have left is whether it is possible to:
Determine the...
If it helps you, I would start by sketching out a graph showing the function of time (Y) and its relationship to t. You can completely ignore X since it will have nothing to do with how quickly Y changes. Y is only a function of time.
From there on out, follow PhanthomJay's suggestions.
Yeah moving terms from one side of the equation to the other is a pain, and if you ever need help with it again, I think I'll take one for the team. :P
10 (:P) s
You're good with question 4 now, too?