Recent content by coolbeans33

srry I forgot to put the "equals zero" in. So I solved for the derivative and I got: yexy+2x/x*exy+2y and the slope of the tangent line at pt (2,0) is 2.

find dy/dx: exy+x2+y2= 5 at point (2,0) I'm confused with finding the derivative with respect to x of exy. this is what I did so far for just this part: exy*d(xy)/dx exy*(y+x*dy/dx) do I need to put the parentheses on here? I thought so because that is the part where I used the product rule...

Re: finding the derivative of ln(1+x)^2 then it would be f(x)= 2ln(1+x) and f'(x)=2/(1+x)So if I want to differentiate f(x)=ln(1+x2)2 it would be 4x/(1+x)2 right?

I need to find f'(x) when f(x)= ln(1+x)2. I started with the chain rule: d[ln(1+x)2]/d(1+x)2 * d(1+x)2/d(1+x) * d(1+x)/dx so 1/(1+x) * 1/(1+x)2​ * 2(1+x) I know something about that is wrong, I'm not sure what.

what are the steps in finding the derivative of the function y=e-.5x and why is the answer zero? sorry I'm posting like 150 threads, I'm just really bad at math.

can you help me find the derivative of: (5t^2+1)4 this is what I did: (5t^2)(ln 5)(2t) * 4(5t^2+1)3 did I do this right?

ok I just figured it out. just to make sure, if you multiply a constant (c) by x or ex, you're left with Cx or Cex right?

this still makes no sense! after I applied the chain rule I got -1A(B+Cex)-2 + d/dx (AB+ACex) the part I don't get is how I'm supposed to take the derivative of the variables. do I just treat them like x and say they're equal to one?

so I was reading my textbook and was showing steps on applying the quotient rule to the function: y=ex/(1+x2) it went from (1+x2)(ex)-(ex)(2x)/(1+x2)2 to ex(1-x)2/(1+x2)2 I understand the first step, but don't get how they got to ex(1-x)2 in the numerator. can someone please explain the...

I know that the derivative of the sqrt x = .5x^-1/2 I think that x^-1 equals 1/x right? so what does .5x^-1/2 equal? I am kind of confused! is it 1/4x?

do I use the power rule or the chain rule first?

A, B, and C are all constants, and the function is A/(B + C*ex)

I need to find the f'(x) when f(x)= A/B+C (ex) so I used the quotient rule to get: (B+Cex)(1) - A(B+Cex)/(B+Cex)2 is this right so far? and if it is, how do I simplify it more?

Re: find derivative with exponential function? ok so I used the product rule for this one, and I got (ex)(sqrt x) * (.5x1/2)(ex) is this right?

f(x)=x2ex the answer is f'(x)=(x2 + 2x)ex but I don't understand how to get there. Also I need to find g'(x) if g(x)=sqrtx(ex) would the answer for the second one be .5x-1/2ex?