Recent content by Count_Chockul

Thank you so much for all your help!

OK So I took your equation and I think that I did the math correct, but I think that some of my conversions are incorrect in places. Anyway: here is what I got diss = m_c/p_w = v_w diss = 227/1 = 227cm^3 Taking that and subtracting the original volume of the can: New Vol =...

I see where I might have gone wrong, but... so should I use this formula to find the water displaced? diss = m_c/p_w = v_w If so that doesn't seem right to me... would I take this new displacement and try to convert it back to Newtons so that I can find the weight difference? After that...

ok, well after looking at this for a VERY long time and using a friends help this is what I have come up with... Vc=282.74cm3 Mc=0.227kg Finding the specific gravity of the can (pc): pc=m/V pc=0.227/0.2827 pc=0.805m3 Taking this and the mass of the can I *think* that I can find the...

OP did you ever figure this out... I have this exact same problem and can't figure it out! As a matter of fact I got the exact same answers as you did above with the add info below: density of can (pc)=0.805cm3 after that I get just as stuck you were.