Recent content by cpashok
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A Definite integral where solution. involves infinity - infinity
oops! {x^(1/2){1+1/x}^(1/2)} / x ^(1/2){1+1/(x^2)}^(1/4) . i got this in the notebook, forgot to use paranthesis and forgot to edit the second term that i copy pasted from the first.- cpashok
- Post #8
- Forum: Calculus and Beyond Homework Help
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A Definite integral where solution. involves infinity - infinity
Correct me if i am wrong. ln [x^(1/2) { 1+ 1/ x^(1/2) } / x^(1/2) { 1+ 1/ x^(1/2) }] I would get ln 1. which is equal to zero and hence the required answer. Thanks a lot Mark 44 and Dick.- cpashok
- Post #6
- Forum: Calculus and Beyond Homework Help
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A Definite integral where solution. involves infinity - infinity
Thank you very much Mark44 and Dick. I got the same integral as Mark44. I understand what Dick is saying but I'm not allowed to use L hospital's rule at school. I can't figure out any other way. Is there an alternate way to evaluate the above integral?- cpashok
- Post #4
- Forum: Calculus and Beyond Homework Help
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A Definite integral where solution. involves infinity - infinity
I have been trying to insert the images and during the edit , accidentally created another post. Please check the other post. http://www.freeimagehosting.net/uploads/3168397520.jpg- cpashok
- Post #3
- Forum: Calculus and Beyond Homework Help
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A Definite integral where solution. involves infinity - infinity
Homework Statement Evaluate the integral. http://www.freeimagehosting.net/uploads/176e17ca2f.jpg Homework Equations http://www.freeimagehosting.net/uploads/3168397520.jpg The Attempt at a Solution http://www.freeimagehosting.net/uploads/3168397520.jpg I am stuck here as the book...- cpashok
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- Definite integral Infinity Integral
- Replies: 8
- Forum: Calculus and Beyond Homework Help
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A Definite integral where solution. involves infinity - infinity
Homework Statement Evaluate the integral. http://www.freeimagehosting.net/uploads/176e17ca2f.jpg Homework Equations The Attempt at a Solution- cpashok
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- Definite integral Infinity Integral
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Length of Curve with Parametric Equations x=cost and y=sint in the xy-plane
Hint: (Zcos t, Zsin t) where Z is a some arbitrary constant(in the set +R) represents a circle. In your case, substitute Z=1, 0<t<pi.- cpashok
- Post #7
- Forum: Calculus and Beyond Homework Help
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Finding the Minimum Hypotenuse of a Right Angled Triangle | Hypotenuse Homework
Yes you're right. I went to school today and got the question sorted out, it wasn't isosceles. A friend of mine verbally stated out the question he had picked up from some guide book, and I seem to have taken it down wrongly, mixed up multiple questions! Sorry about that. I panicked as I had...- cpashok
- Post #8
- Forum: Calculus and Beyond Homework Help
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Finding the Minimum Hypotenuse of a Right Angled Triangle | Hypotenuse Homework
http://img218.imageshack.us/my.php?image=mathsrv7.gif- cpashok
- Post #6
- Forum: Calculus and Beyond Homework Help
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Finding the Minimum Hypotenuse of a Right Angled Triangle | Hypotenuse Homework
Why is the attachment pending approval? why is my question being unanswered? Believe me i tried my best before posting up the question here. Somebody please help me?- cpashok
- Post #4
- Forum: Calculus and Beyond Homework Help
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Finding the Minimum Hypotenuse of a Right Angled Triangle | Hypotenuse Homework
Hi! Thanks for your time. I was not referring to theta as angle BAC or BCA, which is pi/4. For a point X, a and b are fixed, and are related (except that I am unable to figure it out straight). If I can represent h as an equation of a alone, or b alone, or some other variable theta on which a...- cpashok
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding the Minimum Hypotenuse of a Right Angled Triangle | Hypotenuse Homework
Homework Statement a and b are two perpendiculars drawn to the sides from a point on the hypotenuse of a right angled, isoceles triangle. Find the minimum value of the hypotenuse in terms of a and b. Homework Equations ABC is a right angled, isoceles triangle, with AC, the hypotenuse...- cpashok
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- Minima
- Replies: 7
- Forum: Calculus and Beyond Homework Help