Okay, so I looked at it again, and this is what I got.
I found the new acceleration by g(u)cos(30) . I ended up getting a = -2.80 m/s/s.
From there, I plugged it into the distance formula above, leaving me with:
delta_x = t(6.00) + .5(-2.80)t^2
I took the derivative with respect to t...
Homework Statement
A block is given an initial speed of 6.00 m/s as it slides up an inclined plane that makes an angle of 30 degrees with the horizontal. If the coefficient of kinetic friction is .330, how far up the incline will the block go?
Homework Equations
I messed around with...