Recent content by Cronomius

  1. C

    A chain sliding down an incline

    Ok, think i get it, will look into it when i get time :D Again thanks for the help :D
  2. C

    A chain sliding down an incline

    So use Hook's law to find the time it took?
  3. C

    A chain sliding down an incline

    At the moment it doesn't :P
  4. C

    A chain sliding down an incline

    Ok so using my equation above, and then letting x=l since the chain has traveld down the entire slope the equation simplifies down to .5mglsinθ = .5mv^2 which gives me a velocity of v=√glsinθ But then i also had to find how long this took, but since the system has a variable acceleration i...
  5. C

    A chain sliding down an incline

    Thanks for all the help :D I like this forum :D Having a place to go to get the help I need is a great asset :D
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    A chain sliding down an incline

    and will look at those problems now :D thanks :D
  7. C

    A chain sliding down an incline

    Ok, seing as this isn't suppose to be all that complicated making those assumptions seems like a fair bet :D And i take it that my equation using conservation of energy was wrong? even when using those assumptions?
  8. C

    A chain sliding down an incline

    Earlier you made it seem like it was possible to solve this problem using conservation of energy as well, but i needed to use the center of mass of the chain. could i then use mglsin(θ)/2 = mgl((l-x)/l)sin(θ)/2 + .5 (mx/b)v^2 ?
  9. C

    A chain sliding down an incline

    And then I'm confused again :P At the end of the ramp the normal force changes from mgcosθ to just mg, but seing as this is only in a vertical componet as you said it has no impact on the velocity, this i get.
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    A chain sliding down an incline

    Ok, so then i need to take the integral of the acceleration wquation i got? or do i need to redo that as well?
  11. C

    A chain sliding down an incline

    Yeah b was suppose to be l there :P sorry Energy is conserved in the system. When i used F=g(m(l-x)/l)sin(θ) I get the acceleration to be: a=g((l-x)/l)sin(θ) Then using v=v0+a(t-t0) where v0=0 and t0=0 i get: v=gt((l-x)/l)sin(θ) But i can solve it using conservation of energy as well...
  12. C

    A chain sliding down an incline

    So using F=ma i can use a=gsin(θ) and then the mass that is still on the incline as m(b-x)/b? so F=g(m(b-x)/b)sin(θ)?
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    A chain sliding down an incline

    I'm confused :P Yes i am taking calculus I
  14. C

    A chain sliding down an incline

    My first post :D I have an incline of angle (θ) to the horizontal, and a chain of length (l) of a uniform mass (m), I place the chain so that one end is at the bottom of the incline, the entire system is frictionless. I need to find what the velocity is as the last end leaves the incline, and...
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