Recent content by Cryphonus

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    Line Integral: Evaluating Along Circular Path from P1 to P2

    oh sorry i thought it was there E= (x) x - (y) y variables in the paranthesis refers to the direction. i still need to express dl somehow.
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    Line Integral: Evaluating Along Circular Path from P1 to P2

    Homework Statement Evaluate the line integral along the segment P1(0,3) to P2(-3,0) of the circular path shown in figure. Figure basically shows a circle with a radius of 3. The part that i have to evaluate is from the y-axis (P1) to the x-axis (P2), basically a quarter of the circle...
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    Is the function f(m, n) = m^2 + n^2 one-to-one?

    ok since both f(3,2) and f(2,3) points to the same element in the range this function is not one-to-one. We also showed that f(m,n) = f(n,m) does not implies n = m which is basically the same thing. i think I am right this time? ^^ Thanks a lot
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    Is the function f(m, n) = m^2 + n^2 one-to-one?

    oh right, it doesn't implies that m = n; f(3,2) is equal to f(2,3) but with different values of m and n. By the way one to one means if whenever f (a) = f (b) then a = b? so that the every element in domain points to a single unique element in range.
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    Is the function f(m, n) = m^2 + n^2 one-to-one?

    how so? f(m,n) = f(n,m) implies that m=n ? in this case the function should be one-to-one? or am i missing something?
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    Is the function f(m, n) = m^2 + n^2 one-to-one?

    so does that proves that the function is one-to-one?
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    Is the function f(m, n) = m^2 + n^2 one-to-one?

    they are equal since; m^2 +n^2 = n^2 + m^2 ?
  8. C

    Is the function f(m, n) = m^2 + n^2 one-to-one?

    Hey; im kind of stuck with the following question, i would be glad if you can help Homework Statement Determine if the function f : Z x Z --> Z defined by f(m, n) = m^2 + n^2 is one-to-one. Homework Equations if F(x1) = F(x2) implies x1=x2 then the function is one to one...
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    Multiple charges and coulombs law

    Hello there; Why don't you start with drawing a diagram and placing the charges into positions, after you do that consider the E as a vectorial value which affects the charged with the inverse proportional square of radius.So while doing your calculations take note that the values are...
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    Probabilities of this marketing department information

    Please follow the plan that is introduced as the first topic of this section, i assume you didnt understand v part?? If you can clarify tha part that you didnt understand i can help you in a better way. For the v part) (taking reference of your venn diagram in the link) 30 people is...
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    The diffrent frictions and how they apply in life.

    Not really Hazzard, Static friction is a type of friction that only acts on resting objects, and it is always bigger than kinetic friction.. (have you ever did calculations in the class about friction force acting on a moving object? if yes say so) To make it more clear for you...
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    Speed of a rocket between 2 asteroids

    Hello there iirreeek! First i have to suggest you to draw a force diagram, why?.It is because the gravitational force between astoreids and the ship is the thing that is going to put millenium falcon* oops eagle ;) into motion, obviosly it is going to be a motion with acceleration since there...
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    How do you calculate the electric field and voltage for a charged sphere?

    Alright i understood.Thanks for all the help
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    How do you calculate the electric field and voltage for a charged sphere?

    Ok that makes sense except 2 points; First how are we going to find the formula for the other situation, what do we need to change? Second one; For the situation, R<r<infinity , this actually means the point we are considering is somewhere out of the sphere.Are you saying that the E...
  15. C

    Why is the Electron's Momentum Higher in Special Relativity?

    Well it is true but there is something that is not fully clear here; Statement C is also right, if an object is not close to the speed of light the change in its mass can be neglectible,it is just so little.But it is still appliable.So i guess the answer is A but in my opinion statement C...