[FONT="Century Gothic"]The image distance is 144cm, the object distance is 36cm, and the image height is -96cm. I need to find the object's height.
hi / ho = -di / do
-96 / ho = -144 / 36
But now I am unsure of how to bring the -96 over to the other side to have the object's height isolated...
After using the equation 1f = 1÷do + 1÷di I found what the focal point / f was.
Now, what would the focal point represent? Is the focal point the image height or object height in the equation m = hi÷ho = -di÷do
A microscope produces an image that is 1.00 x 10-4 m high from an object that is 4.00 x 10-7m high. What is the magnification of the microscope?
I've already tried applying this with the formula 1f = 1÷do + 1÷di
So: 1f = ( 1÷ 4.00 x 10-7) + ( 1÷ 1.00 x 10-4 )
1f = 250 000 + 1000...