Thank you for your reply. Let's just say that you have no knowledge of what the function does and that you have second derivative information for I in x and y, but not xy t xt and yt. Would you rather use just the first order approximation or does "on average" or with greater probability, the...
I wasn't sure of a place to put it. Taylor series involve taking derivatives? ;) thanks for your answer though. Still looking for a solid mathematical reason why though. Thanks,
Chris
So I'm computing a second order Taylor series expansion on a function that has multiple variables. So far I have this
I(x,y,t)=dI/dx(change in x)+dI/dy(change in y)+dI/dt(change in t)+2nd order terms
Would it still be a better approximation than just he first order if I included some...