So, the "second derivative of displacement s" (the "acceleration a") is equal to 2A. So, what is the coefficient A in s=At^2+Bt+C?
It would be 1. But where are you going with this?
Let me just throw some dummy values out there.
Say my initial velocity is 15 meters/second and the...
To see what the coefficient of t^2 represents, take two derivatives of the displacement s, written as s=At^2+Bt+C, with respect to t.
Ok, the first derivative would be 2At + B and the second derivative would be 2A. I'm not quite sure of the consequences of that, but would you mind helping me...
Oops. I apologize, I just realized this probably is in the wrong forum section. I didn't see the sticky note at first. Sorry never posted here before. Could a moderator move this to the proper forum?
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