Recent content by Cyphin

Wow that actually makes complete sense when represented in that way. But what I've been trying to figure out is how to account for having at least 1 ball in one box how is this accounted for in that permutation? For instance if we were to have at least 2 balls in any box would that change the...

Okay, so you have k elements plus n things - 1 which infers that the total number of things and ways to choose these things is subtracted by 1 because we know we need at least one element in one of the boxes divided by the number of ways n be chosen from the set of k things. Is that somewhere...

No (3 choose 2) would be 1. From what I can tell I need (5 choose 3) would equal 10 which is what I would be looking for if I'm correct? Which would mean I would need ( n + k -1 choose k)?

N is the number of objects, K is the boxes? Am I correct?

Yes the balls are identical and so are the boxes see I got 27 combinations but I just can't wrap my head around a permutation or am I going in the wrong direction completely here?

Homework Statement Determine all possible ways to placing three balls into three boxes, where there may be more than one ball in anyone of the three boxes. Could you determine all possible ways of placing 20 balls in 365 boxes? Homework Equations The Attempt at a Solution I know this problem...