Recent content by Cyrus1

Now i understand! Very nice, thanks ! however, i don't see how this works if the triangle in red is representing the angle of sight. in my head none of the equations would work out. Would appreciate an explanation! THANKS!

I drew it all very detailed and the problem is that the circle only touches a part at the bottom of the extended hypotenuse!

I know the basics. I might post my method tomorrow as i just can't figure out what is wrong with it, but i am interested to know how you are thinking!

Exactly! Any ideas?

Ok i am lost. I have no idea what you did there.

This is not what i did. Interesting, i will try it out and get back to you. Thanks!

I want to calculate the highest possible value for Z, which you can see here. I differentiated a bit at the end when i got a function of h. I probably forgot to mention that it is necessary to have a function f(h)=Z...

That seems reasonable. However i would need to prove that having the eye level at the centre gives the highest angle, something which i have no clue how to do. Should i use a^2=b^2+c^2 - 2bc(cos(A)) ?

Swedish Math problem i got. Seems to be easy. but not quite...? This is a problem i chose because i thought it would be interesting as well as easy, however, i should have known better than to choose the last question in my maths book as my "essay" question. I have done it and i can't see how...