That actually helped, but I have an idea.
The whole point of the question was to design a program in Java to solve the above problem using any two widths entered by the user.
I figured that since Theta is between 0 and 90 degrees, I can run the calculation in a loop 90 times, and get the...
No. I am not studying differential calculus.
the requirement of the question is that I need to be able to enter two widths of both the hallways, and then calculate the length of the longest possible ladder that can be carried to the right-side of the room using this formula: AC = AB + BC =...
In the question, it says that: AC = AB + BC = (8/sin(Theta) ) + (5/cos(Theta) )
I just want to know the angle theta to know the length of AC that constitutes the longest ladder possible to be carried to the right side of the room.
Hey
I was wondering if someone could help me with this. I suspect it has an easy solution, but I just need some verification.
L is a ladder between two hallways. How can someone find the angle theta??
Excuse my silly question, but I would really like some input if possible.
Thanks