Recent content by Da-Force

russ, I think that would be true if you aren't fighting gravity. For example, I push weights up, gravity does negative work and I do positive work. I let the weights fall, I do no work, gravity does positive work. However, if I SLOWLY bring the weights down, while gravity wants to bring the...

Hmm.. as a real life experiment? Magnetic fields and electric fields can do this very easily. If you apply an electric field, a proton will go in the direction of electric field lines, and an electron will go the reverse. Magnetic fields: right hand rule. Otherwise, chroot is right...

That last line, again, is impulse... So in reality, we're just looking at the impulse-momentum combination that produces this force. So, yeah.

For that, I did mean the voltage loss. He's right in his statement So what I was elaborating was that you can reduce almost any simple circuit diagram into a battery and a resistor and simply go on from there and work your way backwards. I'm not even in college yet, phasors aren't exactly...

I meant charges e_e But anyways, resistances can be thought of as 'slowing or resisting' charges which creates a voltage... High resistances like a voltmeter means no (or neglible) current goes through the wire. And mathematics never explain negative/positive signs in magnetism or electricity...

The second law does not state the equation... Newton's second law also states conservation of momentum, and gravitational forces. It REALLY isn't F=ma.. It states that the motion of a mass is accelerated by a force. Motion can be defined as the momentum (p=mv). or you can have F=ma...

Short-circuit means a 0 resistance wire (a perfect ammeter, I believe) is placed across two points... All the current will go through this wire (which is kinda how ammeters work LOLz, if that's an easy way to remember). Mathmatically, don't rely on it... The idea is simple, current wants to go...

Umm... Here's an easy way to devise this. You're right in the assumption that one resistor will take all voltage. So we have ways of changing 3 diff resistances into one resistance. Resistors in series (the current doesn't split) will simply be added (IE: 3 ohms + 6 ohms = 9 ohms total...

Err.. Any old physics book will work... I mean, physics hasn't changed over the years in reality. Older=cheaper too XD

Nobody mentioned this on here Y'all don't understand the idea... What we have here are TWO closed systems. One, the car is traveling at a constant speed, doesn't mean zero acceleration. It could be accelerating radially, thus changing directions (such as traveling around a bend...) So...

Problem is, this is like more-so of a conceptual question. I do know the answer is 3 feet. That's what's so dang confusing... To see your full body/image... I thought 6 feet at first :-P

6-foot tall person stands in front of flat mirror. How tall must mirror be for this person to view his full body/image? <-Yeah, that's a question.

{1 \over C_{tot}} = {1 \over C_1} + {1 \over C_2} Well, what is the exact problem? Like he said above, you would need to know the total capacitance, OR the charge and the potential :-) seeing how C=Q/V. When dealing with electricity, capacitors, and resistors... It's best to write down what...

Well, if you look at it vectorally... I usually assume that going away from the wall will be positive and going towards the wall is negative. So the final momentum minus the initial moment will be your answer. A shortcut (I prefer) is that the mass is 'constant' for this system so all we...

This is actually from my teacher, he's a genius, and it works pretty much every single time :-) No matter what situation... Draw a force-body diagram for every mass/object/thing that has a force acting on it. The sum of the forces in each direction in a SINGLE FORCE-BODY diagram always...