Recent content by dagr8est

Yeah, I don't get how to integrate that. Wouldn't it be something like v^3(t)/(3a(t)) but where does the a(t) come from? It's not a constant so you just can't add it in right?

Given a(t) = -Cv^2(t) where C is a constant, express v(t) and x(t) as explicit functions of time t. Assume v(0) = v0 So I tried integrating both sides of the equation to get: v(t)+C' = -C integral v^2(t) dt but then I how am I supposed to integrate v^2(t) dt... Also, I thought I could do it...