Recent content by DanD

I managed to do this question via the following , calculating B , Then doing the following Power = B*Area of Emitter*Solid Angle of the Pupil* Range of frequencies. Thanks guys !

Sorry my mistake I mean 2.898 . It may have something to do with Planck distribution , calculate B then multiply by some other values to get the right dimensions .. i.e. area , solid angle and frequency. In response to the diameter question in i.) --> P=σAT^4 100= 5.67x10^-8 x Surface Area...

1. 6. A 100 W light bulb is designed to operate with it’s filament at 2000K. If the filament is a perfect cylindrical Black Body and 2 cm long, i) What must it’s diameter be (3 marks) ii) What will be the wavelength of the intensity peak in its emission. (2 marks) iii) You...