well I assumed since hydrogen is a +1 charge and the anion like chlorine is a -1 charge that the charges would cancel each other out. I thought that the charges had to be accounted for if one had like a +2 and one had a -1. I would assume if the orientation was not end on end than yes it would...
welll the orientation is going to be the water molecules surrounding the anion where the positive hydrogen's are going to be towards the negative anion charge. The equation looked like it fit the question lol.
As well I think i solved it where i turned the Debye unit into C*m so this is what i got
(9.0x10^9)(6.17x10^-36)/(1.0x10^9)^2=0.05553N*C which equals 0.05553V/m.
Actually we haven't covered any of this in class we have looked at computer simulations of water in class and that's about it so far so it is me just guessing cause we have not been given any formulas. The formula i have in my thing is from me looking it up online since there is also no textbook...
Suppose that H2O molecule (micro = 1.85 D) approaches an anion (such as Cl-) in the
gas phase (situation typical of the ion-induced nucleation of atmospheric water vapor).
(a) What is the favorable orientation of a molecule? (b) Calculate the electric field (in
V/m) experienced by the...