Recent content by danielassayag

You quoted this: danielassayag said: 1/infinity tends to zero, but only tends, which mean it's not completely 0, there is still some infinitely small value left to it. to then respond: but here is what I wrote: (as you can see it hasnt been edited on the post) I'm interpreting 1/x with x...

in some case, (when x get larger and larger) 1/x tends to zero, but only tends, which mean it's not completely 0, there is still some infinitely small value left to it. If you multiply that infinitely small value of 0 decimal, to an infinitely large integer number, you end multiplying the depth...

Wolfram alpha and microsoft don't seem to implement your understanding of maths, as they don't comprehend that 1/infinity should be undefined. Though they understand the concept of undefined itself, when it comes to dividing 1/0.

I didn't mean to outsmart wolframalpha btw..

You are right. I just realized that 1/x when x gets larger tends to 0. But if x is infinitely smaller, example 1/0.1, 1/0.01.., then it tends to infinity again. So 1/infinity tends both to zero and infinity. So i guess you can call it undefined.

Division by infinity is not undefined. Division by infinity tends to zero, The plot is stretched oppositely whether the number is smaller or greater than one. plot | 1/x | x = -0.1 to 0.1 plot 1/x from x=-100 to 100

Why multiplying 0 by infinity should be zero and not one, when dividing 1 by infinity is 0? the a/b = c equivalent to a = b*c relation doesn't apply here?

As we know those relations are true: if a/b = c, then a = b*c and b = a/c Therefore if 1/ ∞ = 0, ∞ * 0 should be equal to 1 and 1/0 = ∞