Recent content by DannyCPA

You are missing ..TaT., I believe. Thus, computing this should lead to (after simplification): 26 / 210 = 1 / 24 = .0625 Great approach, btw.

Njama, I don't see where the permutation comes in. By your definition, "a..." represents = "THHHHHT222," where 2 is the number of possible outcomes at that position that satisfies this sequence, correct? If so, isn't that 23, which is not P(3,2). And lastly, what about the...

Hmm, your method pretty much is the same as what I utilized to approach this, less different signifiers. Where I used "2," you used a "." This method does seem to work, but I refuse to believe there is no other way other than literally "counting" the possibilities. Combinations/permutations...

Homework Statement Suppose you will toss a coin 10 times. A) Compute the probability of event A that the longest run of consecutive Heads has length 5 (i.e., within your 10 tosses there is a run of 5 Heads in a row, but not 6 consecutive Heads.) B) Compute the probability of the event...

Ah, okay. The typo threw me off. Finally worked out the integral and resulted in that. Thanks.

Yah, deleted the post after I looked a little closer. However, I am still not sure why mj12 has an addition between uv + \int\ vdu when it should be a subtraction?