Recent content by dansbr

[b]1. a pile driver of mass 250kg is allowed to fall from rest through a distance of 2m on to a 400kg steel pile to drive it into the ground. Each impact drives the pile into the ground by 150mm. assuming that the pile driver remains in contact with the pile after impact and that momentum is...

so should i use KE=MV² and P=Fv

[b]1. A racing car of mass 950kg accelerates from 30km/h to 170km/h over a distance of 220 meters. Frictional forces and wind resistance can be assumed to be 750N. Determine the tractive force produced by the car to provide this acceleration The car finally reaches a speed of 250km/h...

Thanks good help

Then would the change in kinetic energy of the system be the kinetic energy of the intact vehicle minus the kinetic energy of the heavier of the two separate bits?

Is the answer 6454km/h

So the momentum of the intact vehicle is 1300x7000=9100000 Does that mean the sum of the momentums of the separate parts equal the momentum of the intact vehicle.

So if momentum is f=mv Would the momentum of the intact vehicle be (200x10000)+(1100x v?) Am still not sure about this

the space vehicle is traveling at 7000km/h. i don't know the mass of it but wouldn't it be the sum of the sections so 1100+200=1300kg

[b]1. Somebody help explain how to do this for me, am not looking answer, an explanation so i can solve it would be great. A space vehicle traveling at a velocity of 7000km/h separates into two sections of mass 1100kg and 200kg. the two parts continue moving in the same direction with the...