Recent content by danut

My best guess is that the multiple is 2, like adding up the distances that the 2 masses travel: y' = y + y = 2y? I use the word guess because I feel like there's so much nuance to this sort of problems and I'm definitely seeming to be missing some of it 😔

I think I do now 😔 Could it be that a1 = a2 = a, and a3 = a1 + a2 = 2a (of course, in absolute value)? I really hope I'm not mistaken!!

Oh, I see that acceleration is 0 in my case, could that be right?

I did think about it, because the T would cancel out. a = g(m₃ - m₁ - m₂)/(m₁ + m₂ + m₃) (1) => T = m₁(a + g) T = m₁g[(m₃ - m₁ - m₂)/(m₁ + m₂ + m₃) + 1] T = m₁g[2m₃/(m₁ + m₂ + m₃)] T = g[2m₁m₃/(m₁ + m₂ + m₃)] which ultimately is 9,81N. Is however the solution that I thought of correct...

I'm struggling to get to the correct answer, which I posted down bellow. The pulleys are ideal, so I figured that m₁ and m₂ will both move upwards (towards the ceiling?) with the acceleration a, while m₃ will move downwards with the acceleration -a. Let T be the tension in the string which...

I apologize and thank you, will do that from now on!! So V1 = V0*k/(k+1) and V2 = V0/(k+1). I wrote the equation p2 - p1 = p2' - p1' in terms of ν, R, T and the corresponding volumes and finally got the correct answer!! Thank you so much, I've struggled with this problem for the longest time.

First, I thought of the forces which are acting upon the piston. F1 + G = F2, where F1 = p1 * S and F2 = p2 * S p1 + mg/S = p2 I figured that before and after the gas' temperature rises, the piston has to be at equilibrium, so p2 - p1 = p2' - p1'. p1V1 = niu * R * T1 p2V2 = niu * R * T1 =>...