Recent content by dartingeyes

Thank you. This tracks for me.

I want to understand how the two equations in the picture are the same. I am confused because \nu=c/\lambda. This would mean that the term on the right side of the equation in the square root, call it x, would then become x^-1. The resulting equation being \Delta\lambda = \lambda x^-1. But...

I have solved this. the two angular separations are found by: arcsin( m * 605/[(1/31.6)*1e6]) - arcsin( m * 600/[(1/31.6)*1e6]) where m=1 or 40. By multiplying the difference by 180/pi, you get the desired result.

I realize that d= 1/31.6 * 1e6, so that the units do work out. but still i do not get the right answer

Hello, I am attempting to understand and simulate an echelle grating. The thorlabs website has somewhat of an explanation as to how they work...(here). In the echelle section they calculate the spacing in degrees of 600 nm and 605 nm at different orders. They use an example grating of 31.6...