Recent content by dat240

Okay, so let me try again. Tilting the rod a bit shows that the springs are always applying equivalent restorative forces. They are also applying equivalent torques since the forces are symmetrical about the point of rotation. The torques act in the same rotational direction. So, 2τ =...

Thank you. I'm away from my notebook right now, but I will think about what you said and give it another (hopefully better) shot when I get home.

No. I'm an intro physics student, and we just got to SHM yesterday. I've reviewed my book and notes but am not yet at a level where I understand much about it. I'm not looking for free answers. I'm looking for help understanding the concepts so I can apply them in this and other problems. I...

I feel like I'm just clutching at equations, but I'll try. I saw that the physical pendulum equation was T = 2π(I/mgh)^(1/2). For a thin rod about axis through center perpendicular to length, I = (1/12)ML^2 Since I'm not dealing with gravitational potential, I wanted to substitute the...

Not sure if my attachment worked... going to try to post it again here.

Homework Statement A pendulum consists of a stick of length L and mass M that is pivoted about its center, and attached to a pair of springs of stiffness k. As shown in attached pic, the springs are symmetric about the pivot, and the distance between them is l. a) Find the natural...