Recent content by datinker

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    Calculating Liquid Level in 38,500 bbl Tank Facility

    Whoops mistyped that. I meant: Pin = (47ft/(47ft-32ft))(10^5 Pa) = 313,333.3 Pa But that doesn't change the over-pressure from the oil difference.
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    Calculating Liquid Level in 38,500 bbl Tank Facility

    Would this make sense, kind of modified the method, but used many of the same ideas. Given: htotal = 47 ft ρoil = 815.6 kg/m3 Temperature is constant g=9.8 m/s2 Pout = 10^5 Pa hreading1=32ft hreading2=15ft pin/pout =((htotal))/((htotal-hreading1)) Pin = (47ft/(47ft-15ft))(10^5 Pa) =...
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    Calculating Liquid Level in 38,500 bbl Tank Facility

    Ah, so just Boyle's law. PV=k... or P1V1 = P2V2. So simply put you are saying (P_out)(h_total)= (P_inside)(h_total - h_reading)? And the two times you were comparing were before any oil was in the tank, and when it was completely filled? It makes sense, somehow we're missing something though...
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    Calculating Liquid Level in 38,500 bbl Tank Facility

    I don't think there is additional air volume. I'm with you though, unless there is not some unknown vent, I'm not sure how it is possible that the height is less than 120. Are you sure that pin/pout=htota/(lhtotal−32ft) is correct? Where did you get that from?
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    Calculating Liquid Level in 38,500 bbl Tank Facility

    That image is right. I talked to my boss this morning. He said that all the calculations made sense, but assured me there was an error somewhere as the total height of the pipe is actually 47 ft (not 120). I told him that this information would have been useful to know before. He also...
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    Calculating Liquid Level in 38,500 bbl Tank Facility

    Wait wait wait, if you enter the constants you assumed ( pout=10^5 Pa, ρ≈1g/cm3, g=10m/s^2), into the derived formula htotal=32ft+32pout12ρg, the result is around 58, not 120. However, when I work it using metric units, it comes out to about 34.97, or about 120ft! What?
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    Calculating Liquid Level in 38,500 bbl Tank Facility

    Nevermind, works both ways!
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    Calculating Liquid Level in 38,500 bbl Tank Facility

    Thank you! Yes, that's the first thing I suggested, why not just drill the vent hole? If you were to use ρ≈1g/cm3 and g=10m/s^2, wouldn't you first need to convert the h to SI units as well? Just a thought. Other than that, looks good. I've been stuck trying to use Boyle's law and getting...
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    Calculating Liquid Level in 38,500 bbl Tank Facility

    So I work for a drilling company that stores oil in large cylindrical tank facilities. The total volume of each tank is 38,500 bbls. In each specific tank facility, a radar tank gauge sits atop a 10" pipe inside the main tank, measuring the level of the liquid inside the pipe. Usually, a...
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