Recent content by daveamal

Oh I see, this makes things simple. Thanks!

Oh, there was some problem with the web-assign question, so it was showing wrong. Thanks for the help though :D

For phase constant p, I found the D at around 0.15 m. Than as you said, I used 0.15=1.5sin(1.2κ-p) and got p as -5.4 which I rounded to -5. The web-assign says that both ω and p are correct. I don't know why I get the equation wrong.

Thanks! I found time period (T) by approximating from the graph, i.e (1.28-0.61) which is 0.67. Then I found ω by using the formula and got 9.38 rad/sec. Is that the correct way?

Homework Statement The time plot for a wave of wavelength 0.68 m, moving toward the right, is shown at x = 1.2 m in the figure below. (Assume the wave is a sine wave and that it is propagating to the right.) (a) What is the angular frequency of the wave? (b) What is the speed of the wave...

Yup, got it. Thanks a lot everyone, you guys are genius :D

ok so I got the relation between radii and angular velocities: ω1/ω2=R2/R1 While by conservation of momentum: I1ω1+I2(-(ω2))=I1newω1+I2(-(newω2)) Is this correct?

oh no, That was wrong, even the I's will change den, but how?

ok, So will the 2 equations be: ω1/ω2=newω1/newω2 and Angular momentum= I1newω1+I2newω2 Then we will find new omega's?

I still don't understand what I did wrong? How does the radius come into consideration?

Ok but how to find new ω by using R1ω1=R2ω2 ?

How did you find new w s? What did you do with the total angular momentum and R1 w1 = R2 W2 ?

I did the steps and got the answer as 36900.17 joules, but it says that the answer is still wrong.

Oh ,they are in opposite direction, it would be: ω=ω1I1-ω2I2/(I1+I2) Ryt?

Stuck in this question -- 2 spinning disks brought together... Two disks are spinning freely about axes that run through their respective centres. The larger disk (R1 = 1.42 m) has a moment of inertia of 1180 kg · m2 and an angular speed of 4.0 rad/s. The smaller disk (R2 = 0.60 m) has a...