Recent content by David_Vancouver

But aren't those suggestive calculations definitive? That is, they are always true?

Hi, Why is it, that when ever epsilon-delta proofs are done, once delta is found in terms of epsilon, it is reinputed through again? Is there any point to this really?

Sorry this part: if 0 < |x + 2| < 1 then, -3 < x < -1 |x - 2| < 5 is a "side part"

Perhaps this way would work: Prove that lim x->-2 (x^2-1)=3 let E > 0 be given and: |f(x) - L| = |x^2 - 4| = |(x - 2)(x + 2)| = |x - 2||x + 2| if 0 < |x + 2| < 1 then, -3 < x < -1 |x - 2| < 5 < 5|x + 2| therefore: if 0 < |x + 2| < 1 and 5|x + 2| < E then by...