Recent content by davidco

Ok I gotcha thanks a whole lot, so for my part B I just use this equation Delta x=1/2at^2 solve for t For part C i use V=at Are they correct? If so what is my Delta x

Ok I might just have it: This is what i did N=mgcos theta N=(13.2)(9.8)cos(26.2) N=116 Then I use a=Fapp-uN-mg(sin theta)/m a=0-(0.365)(116)-(13.2kg)(9.8m/s)(0.441)/13.2kg a=? Are my numbers mostly right? Im concerned about the -(minus) signs because I am getting negative...

Thanx again Learn, the website was a lot of help. What I was able to get from it was that the overal equation i need for acceleration is: a=Fapp-un-mg(sin theta)/m Is this the correct formula? If so what is my Fapp and un?

Ok, So my Normal force would be 13.2kg(9.8m/s^2)=129.36N correct? Then I take my friction formula and do 0.365(129.36N)=47.21 correct?

Thank you but still alittle confused, So I should just use the EFX=max equation only? Will my EFx equal my friction .365 correct? Im sort of confused would my equation look lke this: (.365)/13.2kg=a and what importance is my theta of 26.2 degrees?

Homework Statement Oscar the otter is having fun sliding down a mud bank. Oscar has a mass m=13.2kg The length of the mud bank is L=4m The coefficient of kinetic friction between Oscar and the bank is MU=.365 The angle the mud bank makes W.R.T. the horizontal is theta=26.2 degrees...

Question so if vertical speed= deltaV/T,would my deltaV= .705m/s?I got .705m/s from my average velocity equation which was 16000m/22680s=.705m/s for avgV. Is average vertical velocity and vertical velocity the same equation?

Thanx, For my average speed =total distance/total time,do I use the 16000m for total distance/6.18hrs or do i convert hrs to seconds. Since my answer has to be in m/s?

Thanx Learn, Ok so if I subtract the H2=2746m- 511m=my distance is 2235m So to find theta I did this: sin theta=opp/hyp sin theta=2235m/16000 theta=7.98 degrees or 8 degrees Please tell me this is correct

Thank you learn, But I am wondering if my hyp=16000m and I am trying to find theta. what's my opp or how do i find my opp.?

Hotvette thanks a lot for the help just got a few more questions. If your talking in terms of a triangle L1 would represent my hypotenuse I believe. So would 16000m be my hypotenuse is what your suggesting. But don't I have to choose the equation involving the hypotenuse to find the angle...

Homework Statement Brandon is climbing a mountain. He starts from an elevation of H1=511m above sea level. In 6.18 hours he climbs to an elevation of H2=2746m above sea level. The length of his path is L1=16000m. A)What is the average angle of ascent the path makes with the...