Recent content by Dazz4C

Don't know how you got that; but it should leave you with a matrix where the determinant is 0, thus the matrix does not have a unique answer and cannot be solved. For example, although your answer for the prices is technically correct; I can say: bread = $4 veg = $2 meat = $20 or bread = $4...

Two vectors form a plane in between them...question is asking for when r is coplanar to q * p. Correct me if I'm wrong. Can be solved by using 0 = r*(q*p)

Your value for y is correct, but I don't understand how you went from (y*3) to 37. Unless it was a typo and was meant to be 3y. You should also be stating why you have it equate to 0.

Check page 204 in your lecture notes...;) and yes, that is incorrect. Hint: a * b = i|ad-bc|-j|ad-bc|+k|ad-bc|

Are you expanding using determinants?...you will get a different answer.

Uhm...what about now?

Ahh...okay I understand what you mean. So would it be somewhat like this diagram? (attached)

Well, if we know that the frictional force and force from gravity cancels (equals zero) then we can say that Friction Force=Gravity Force. Since we also know that Gravity due to acceleration = mass*gravity*Sin theta (Vector Quantity), then Friction Force is also equal to mass*gravity*Sin theta...

Righto, here's my new attempt: We know: Weight of Box (Magnitude a) of 15kg Gravity's Force (Magnitude b) which acts down on the box 9.8ms-2 Friction is unknown Angle between is 30 Friction is a vector quantity, so we use cross product ||a||*||b||*Sin Theta So: ||a||\times||b||\times...

The question is off a worksheet which had required me to use Dot/Cross Product all the way through it, so I've kind of assumed that I'd have to use it for this question.

Homework Statement Given an object of mass 15kg sits on a slide, at an angle of 30 degrees to the horizontal, what is the magnitude of the frictional force acting on the box if the box does not slide down? Homework Equations So, I know this is a scalar vector; so I'll be using the Dot...

I see. Thanks guys :).

But even then, a deposit of 25.5 Joules is not alot...now you've got me thinking. Perhaps, as you said the particle deposits energy systematically along its path of travel(?) it might be 0.3J of energy radiated onto cells? This whole thing is confusing :(.

Hi Everyone, I was just preparing for an exam I have next week regarding the use of Po-210 on Aleksandr Litvinenko. As I came across doing some calculations, something got me puzzled...the 'whole body dose' of energy is extremely low and to me shows no real significance. I'll show you what I...

The brushes are making contact with the circuit. But the thing is, if I put it in parallel to the motor, the input voltage won't be accurate...because the armature on the coil has half the insulation scraped off for the coil to discharge after half a rotation, allowing more force to turn the...