Recent content by DBLE

Oh Snap! I got it! haha One example would be if the object is in uniform circular motion. The centripetal force is always perpendicular to the velocity of the ball. So kinetic energy does not change. Thank you so much for the time and patience cepheid and Matterwave =) really appreciate it.

The two forces are perpendicular to each other, as such no work is done and there will be no change in kinetic energy. Since the problem doesn't state the relationship between the net force and the direction of motion of the object, we cannot determine if Kinetic Energy changes?

If an object is in motion and the force applied is not in the direction of motion, than there will be no work done as such no kinetic energy change. So with the problem not stating what situation the object and force are in, it is insufficient to determine whether KE would change. Am I closer?

Ok I think I got it. I do NOT have to calculate any values, but determine whether or not a change in Kinetic Energy would occur, given the information above? So there isn't sufficient information provided, but why is it so? I'm sorry if it's getting frustrating =S I really do appreciate your...

In other words, is it possible for me to calculate a change if there is any, with the information given? I would say yes, I would have enough information to know if the kinetic energy changes, given the external force and the mass of the object.

If there is a net force acting on the object, the object moves. Work done can be determined and so change in Kinetic Energy?

I see what you mean. Hmm.. I would say that yes, there is sufficient information as with force, the acceleration of the object (if it accelerates or moves) can be found. For Kinetic Energy, insufficient as I would need work done, and that requires distance the object travels. Would that be a...

Homework Statement A net external force acts on an object of mass m. Is this information sufficient to conclude that (i) the velocity of the object changes? (ii) the kinetic energy of the object changes? (iii) the speed of'the object changes? Explain your answers in each case.Homework...

Awesome! Thank you Dr. Vela =)

Ok, I think I have it. I can't just assume that they can divided by two. So using some algebra, if the observer sees the two ships as equal in length, therefore to the observer, they are traveling at an equal speed, V using Velocity Addition formula: 0.58c = -2v/ *squareroot*(1 -...

haha ahh, I see. thought as much for the first part. So if I look in the perspective of the 3rd frame where both ships are of equal length, would the relative speed of each spaceship be 0.29c moving towards each other? (0.58c / 2) So relative to the 3rd observer the length of each...

Homework Statement Two identical spaceship A and B, each 200m long in its rest frame, pass one another traveling in opposite directions. According to a passenger in spaceship B, the relative velocity of the two ships is 0.58c. What is the length of each spaceship in a reference frame in...