Recent content by dcgirl16

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    Solving equations - When to take logarithms?

    How do i know when to take the ln of both sides to solve an equation for example would i for y=10^(1-x)-(1-x)^10
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    Why Do We Use Logarithmic Differentiation for Functions Involving ln and e?

    the last part i don't know how they got any of it they got xlnx/e^x[1/x+(1/xlnx)-1]
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    Why Do We Use Logarithmic Differentiation for Functions Involving ln and e?

    oh right i forgot about that thanks what about the next part (1/y) dy/dx=1/x+1/lnx(1/x)-1 again i understand it until the last part..i thought the derivative of e^x was just e^x..why is it 1
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    Why Do We Use Logarithmic Differentiation for Functions Involving ln and e?

    I'm struggling taking the derivatives of anything with ln or e in it. For example the question y=xlnx/e^x,i have the solution and the first step they have is lny=lnx+ln(lnx)-lne^x. I understand what to do until the last part why is the e^x on top now? If anyone has the time to help me figure...
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    Solving for x Intercepts to Polynomial Functions

    so how do i do it. i was moving that over to solve for x
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    Solving for x Intercepts to Polynomial Functions

    I'm having trouble finding x intercepts i have the question x^3-9x^2+15x+30 and by setting y=0 i got -30=x(x^2-9x+15) I used the quadratic formula to find that x^2-9x+15 give me no real roots, so the only intercept would be x=0. But this would also mean that the yintercept is 0 and i found that...
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    Calculating the Speed of a 4m Ladder Sliding Down a Wall

    if i knew how to do this i wouldn't be on this site, yeah it is a hwk question but its a general question that pretty much sums up everything i don't know. its not like I am using this to try and get you to do my hwk for me its so i can understand how to do it.
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    Calculating the Speed of a 4m Ladder Sliding Down a Wall

    a ladder 4m long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a speed of 30cm/s. How quickly is the top of the ladder sliding down the wall when the bottom of the ladder is 2m from the wall.
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    If xy^2=12 and dy/dt=6, find dx/dt when y=2

    If xy^2=12 and dy/dt=6, find dx/dt when y=2 The way i thought to do this would be (1)(y^2)+x(y)(dy/dt)=0 but i don't know x so this isn't working, what am i doing wrong
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    Can someone help explain what the graph of 1000-10(x-1)^(4/3)/x^1/3

    can someone help explain what the graph of 1000-10(x-1)^(4/3)/3rd root of x would look like
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    Trouble using the chain rule product rule and quotient rule

    ok that workedi got the right answer thanks for your help
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    Trouble using the chain rule product rule and quotient rule

    my first thought would be to multiple the 8x and -3 through their brackets then combine like terms?
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    Trouble using the chain rule product rule and quotient rule

    would it be ((x^2-1)^3)(1)(8X)(2-3X)+(x^2-1)(-3) ?
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    Trouble using the chain rule product rule and quotient rule

    i should have a 1 in there before the plus sign too
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